Sergei and Yulia Skripal were poisoned by a chemical substance BZ, which was in service in the United States and Britain, reports Meduza.
As Russian Foreign Minister Sergey Lavrov said on Saturday, experts from the Swiss Center for Radiological and Chemical-Biological Analysis, who examined the samples taken from the site of poisoning of the former intelligence officer and his daughter in Salisbury, came to this conclusion.
The samples also revealed the presence of a poison nerve agent A234, he said.
According to the Russian minister, in the report of the Organization for the Prohibition of Chemical Weapons the term "Novichok" is not mentioned at all.
"There is a long chemical formula, which, according to our experts, indicates the substance that was developed in many countries, and does not represent any special secret," Lavrov said.
Note that substance BZ is a chemical warfare agent. Its use was reported during the Vietnam War.
As we reported earlier, Sergei Skripal and his daughter Yulia were poisoned in British Salisbury. Later, Theresa May, British PM, stated that Russia was responsible for that, and the investigation has confirmed the use of the Novichok nerve agent, which is produced in Russia.
The Great Britain expelled 23 Russian diplomats, which was supported by the USA, Canada, Ukraine and many other European states.
The representative of the OPCW promised to provide the results of the substance examination.
As it was reported earlier, Yulia Skripal recovered consciousness and started speaking after she was poisoned in Salisbury. Later, the doctors said that she was getting better, she could eat and drink without any help.
The Russian Embassy in Britain demanded to have access to Skripal’s daughter, but the British authorities rejected the request.
The London Police has made the first statement of Yulia Skripal public. She thanked everyone for the support, she thanked the doctors and bypassers for their help.
The doctors stated that Sergei Skripal’s health condition is no longer considered critical.